Optics 11 Homework Solutions

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Solutions:

  1. I did a google search on "Schott PDF N-BK7" to get the data sheets. N-BK7 has a V_D of 64.17, and P_D,C of 0.3076. N-SF6 has a V_D of 25.36 and a P_D,C of 0.2867. So the secondary color is 78*(0.3076-0.2867)/(64.17-25.36)=42.8 microns (thanks to my coworker "P")
  2. Using a similiar google serach for ohara glas.... The data is presented a little differently and it requires more calculations. S-FPL53, V_D is 95.0, P_D,C = (n_D - n_F)/(n_f-n_C) = 0.00462/0.001417 = 0.30671. For S-BSM81, V_D is 60.1, P_D,C = (n_D - n_F)/(n_f-n_C) =0.003271/ 0.01065 = 0.3072. So the secondary is 50 * (003271 - 0.01065 ) / (95-60.1) or 0.745 microns!!!!! Very small since this glass combination has very similar partial dispersion! 
  3. Normal glass slope is 1/2000,,. so secondary is Slope*EFL or 100 / 2000 or 50 microns
  4. D
  5. True
  6. Partial dispersion is (1.92245-1.95800)/(1.95800-1.90916) = 0.272
  7. Dispersion is (1.92245-1)/(1.95800-1.90916) = 18.9
6 and 7 indices are simply S-NPH2 so you can check your work via their data sheet
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